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5c^2+5c=36
We move all terms to the left:
5c^2+5c-(36)=0
a = 5; b = 5; c = -36;
Δ = b2-4ac
Δ = 52-4·5·(-36)
Δ = 745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{745}}{2*5}=\frac{-5-\sqrt{745}}{10} $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{745}}{2*5}=\frac{-5+\sqrt{745}}{10} $
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